56x^2+252x-504=0

Solution for 56x^2+252x-504=0 equation:

56x^2+252x-504=0

a = 56; b = 252; c = -504;
Δ = b2-4ac
Δ = 2522-4·56·(-504)
Δ = 176400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{176400}=420$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(252)-420}{2*56}=\frac{-672}{112}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(252)+420}{2*56}=\frac{168}{112}
=1+1/2
$